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sodium chloride (nacl) dissociates into two ions in water: na and cl-. if the solution in question 8 contained 0.1m sodium chloride rather than 0.1m sucrose, what would the water potential be of the solution?



Answer :

The water potential of the solution when NaCl dissociates into ions is -4.8 bars.

The formula for calculating water potential ψ

ψ = ψs + ψp

where ψs is the osmotic or solute potential and ψp is the pressure potential. Water potential is a measure of water's ability to do work.

ψs = -i CRT

i = 1.0 for sucrose ; Under standard atmospheric conditions

Value of universal pressure or gas constant R = 0.0831 bar Liter/mole K

Standard temperature T = 293 K

C = molar concentration = 0.1 mole/L

Thus Water potential ψ of the solution = (-1)(0.1 mole/L)( 0.0831 bar Liter / mole K)(293 K) = -4.8 bars

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