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two ice skaters stand facing each other at rest on a frozen pond. they push off against one another and the 61 kg skater acquires a speed of 0.75 m/s. if the other skater acquires a speed of 0.89 m/s, what is her mass in kilograms?



Answer :

The mass of the other skater who is pushed is 51.4 kilograms.

According to the law of conservation of momentum,

The total linear momentum is always conserved in a system if no external force is applied.

So. we can write,

Initial momentum = final momentum

Initial momentum is zero as both the skater are at rest.

So, Final momentum should be 0,

Final momentum = 0

M₁V₁ + M₂V₂ = 0

M₁ is the mass of first skater,

V₁ is the final speed of the first skater,

M₂ is the mass of the second skater,

V₂ is the final speed of the second skater, V₂ will taken as negative because the second skater is pushed into opposite direction,

Putting all the values,

61(0.75) = -M₂(-0.89)

M₂ = 51.4 Kg.

So, the mass of the skater is 51.4 kg.

To know more about Linear momentum, visit,

https://brainly.com/question/7538238

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