The approximate age of the bone is 22920
The half-life of an isotope is characterized as the sum of time it takes for there to be half the beginning sum of the radioactive isotope present.
since we know for half time
N = N₀(1/2) n ..........1
where n is the new amount whereas N₀ is the initial amount and n is the number of half time
since the ratio of 14c:12c is 1/16
so the equation 1 gets converted to
N/No =(1/2)n
=>1/16 = (1/2)n
=>(1/2)4 = (1/2)n
=> n= 4
So the age of the bone will be 4* 5730 =22920
to know more about half time refer to the link https://brainly.com/question/19472025?referrer=searchResults.
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You find a piece of bone that has a 14c/12c ratio that is 1/16 that of the atmospheric 14c/12c ratio. If the half-life of 14C is 57305730 years what is the approximate age of the bone?