rocket a passes earth at a speed of 0.70 c. at the same time, rocket b passes earth moving 0.86 c relative to earth in the same direction. how fast is b moving relative to a when it passes a?



Answer :

Rocket B's speed in relation to rocket A is 0.4c

If the two frames of reference's directions are at odds with one another, the two frames of reference would see the relative speed as the total of their individual speeds. Furthermore, if the motion of the two frames is parallel, relative speed would be seen as the difference between the individual speeds.

The Earth's frame of reference is at rest, but the two rockets passing by are traveling relativistically with respect to Earth.

Since both rockets are moving in the same general direction, rocket B's relative speed to rocket A is equal to the difference between the two rockets' individual speeds.

Speed of rocket A is v = 0.70c

speed of the rocket B is u =0.86c

let,

speed of the rocket B with respect to rocket A is u₁

Now,

u₁ = (u - v) / [(1 - u) * (v / c²)]

u₁ = (0.86 - 0.70) / (1 - 0.86 * 0.70 / c²)

u₁ = 0.16 / (1 - 0.6) = 0.16 / 0.4

∴ u₁ = 0.4c

To know more about frames of reference, refer to this link:

https://brainly.com/question/9820962

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