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if the average power requirement in your home is 3.8kw and you can convert solar power to electirc power with 11% effciency how large a collector area will you need to meet all your household energy requirements



Answer :

A collector area of 34.4 m² is needed to meet household energy needs where the average power requirement at home is 3.8kW

We know that the efficiency of solar panels can be calculated by using the formula

efficiency E = (panel power (in kW) / panel area ) * 100%    (1)

Given efficiency E = 11 %

panel power required P = 3.8 kW

Let the panel area required to meet all household energy requirements be A

Thus from formula (1)

11 = (3.8 / A) * 100

⇒ A = (3.8 * 100) / 11

⇒ A = 34.54 m²

Thus the collector area of solar panels required to meet household energy requirements is A = 34.54 m²

Problem based on solar panel efficiency

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