a current density of 8.50 10-13 a/m2 exists in the atmosphere at a location where the electric field is 168 v/m. calculate the electrical conductivity of the earth's atmosphere in this region.

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26-10-2022
Physics

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a current density of 8.50 10-13 a/m2 exists in the atmosphere at a location where the electric field is 168 v/m. calculate the electrical conductivity of the earth's atmosphere in this region.

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qwterabite qwterabite · Answer 1 · 2022-10-29T04:42:02-04:00

The electrical conductivity of the earth's atmosphere in this region is 5.059 x10^-15 mho

Electrical conductivity may be an estimation of how effortlessly a material permits electric current to stream through it. We are given the current density which is 8.50 10-13 a/m2 and the magnitude of the electric field which is 168 v/m.

So the formula for calculating the conductivity is

σ=J/E, here the E is the magnitude of the electric field and the J is the current density

= 8.50 10-13 a/m2 / 168 v/m

=5.059 x10^-15 mho

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