Answer :
Both of the bullets will hit the ground at the same time.
If we ignore any kind of air resistance and assume the surface of earth to be completely flat.
Let us first analyze the motion of the dropped bullet,
The initial velocity U is zero, if the height is h, and the acceleration is only because of gravity so it is g, then the time t is,
We can write,
H = ut + 1/2gt²
H = 1/2at²
t = √(2H/g)
Now, let us assume that the bullet is fired with some initial velocity u,
We have to notice that the velocity here is completely in the horizontal direction, so, analyzing the vertical motion,
We can write,
H = ut+1/2gt²
There is no initial velocity in vertical direction,
t = √(2H/g)
So, the time to hit the ground is same in both the cases.
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