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a package is dropped from a helicopter moving upward at 15 m/s. if it takes 8 s before the package strikes the ground, how high above the ground was the package when it was released if air resistance is negligible?



Answer :

The height from which the package was dropped is 440m.

As we are neglecting the air resistance, the acceleration of the package remains constant,

We can use the equation of motion,

We know,

The time taken by the package to come down is 8 seconds and the speed with which is dropped is 15m/s.

So, using the equation,

S = ut + 1/2gt²

Where,

S is the displacement or vertical height of the package,

u is initial speed,

t is the time taken by package to come down,

g is acceleration due to gravity whose value is 10m/s².

So, putting all the values,

S = 15(8)+1/2(10)(8)²

S = 440 meters.

So, the height of the package is 440 meters.

To know more about equation of motion, visit,

https://brainly.com/question/28180340

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