Answer :
The terminal speed of the object falling down is 66.67 m/s.
The terminal speed acquired by the body when,
Weight of the body = Drag force of the body
It is given,
Drag force is directly proportional to the speed,
So,
F = CV
Where F is drag force,
V is the speed,
C is the constant,
So, it can be written as C = F/V.
The weight of the body = mg
The weight of the body = 10m
M is the mass and g is the acceleration due to gravity,
The drag force when the speed is 20m/s.
Drag force = ma
a is the acceleration during the drag force which is given to be 3m/s²,
Drag force = 3m
Now we can write,
F₁/V₁ = F₂/V₂
F₁ is the drag force at 20m/s speed.
F₂ is the weight of the body and V₂ is the terminal speed,
Now, it can be written,
3m/20 = 10m/V₂
V₂ = 66.67 m/s.
So, the terminal speed is 66.67m/s.
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