The probability that the instrument somehow doesn't fail in an 8-hour shift is 0.886 for the frequency of testing instrument failures due to contamination particles on the item is a Poisson random variable with either a mean of 0.015 errors per hour.
Using Poisson Distribution,
Let X be the number of failures in 8 hours. Because there are 8 hours instead of 1, the mean will be 8 × 0.015 = 0.12.
As a result, the opportunity of no failures during this period is increased.
P(X = 0), is
P(0) = ([tex]e^{-0.12}[/tex] × [tex](0.24)^{0}[/tex]) ÷ 0!
P(0) = (0.886 × 1) ÷ 1
P(0) = 0.886
The probability that the instrument will not fail during an 8-hour shift is 0.886.
Learn more about the Poisson Distribution at
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