a report states that 46% of home owners have a vegetable garden. how large a sample is needed to estimate the true proportion of homeowners who have vegetable gardens to within 4 percentage points with 92% confidence?



Answer :

The sample required to estimate the true proportion of homeowners who have vegetable gardens is 472.

The formula for calculating a confidence interval proportion is given by

E = Z×√(p×q÷n).

where

E = maximum allowance of error between the true proportion and the sampling proportion.

Z = the confidence interval in standard error units.

p = The estimated proportion of success

q = (1-p), or the estimated proportion of failures.

n = no of items in a sample.

Solving the equation for n, we get

n = (Z²×p×q)÷(E²)

Substituting the values based on the equation based on the sampling design, we get

n = [1.7507² × 0.44 × 0.56]÷(0.04)²

Solving the equation, the value of n is obtained as

n = 472, when rounded up.

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