is it safe to drive your 1600-kg car at a speed of 27 m/s around a level highway curve of radius 150 m if the effective coefficient of static friction between the car and the road is 0.40? explain



Answer :

It is not safe to drive at this speed since the centrifugal force is larger than the force due to friction.

The centrifugal force on car is

F=mv²/r

F= 1600*27*27/150

F=7776N

force due to static friction is

Fst=μN

   = 0.4*1600*9.8

   =6272N

The frictional force between a washer and a metal rod is then compared to the centrifugal force necessary to overcome static friction between a washer and a rod that is experiencing rotational acceleration. This equivalence allows us to compute the theoretical velocity at which the washer starts to slip off the rod. Static friction now enters the picture to prevent slipping before it even begins. By acting radially inward to the turn, it resists the motion by acting in the opposite direction. As a result, if you think of the turn as a portion of a circle, static friction will act as the centripetal force.

Learn more about centrifugal force here:

https://brainly.com/question/13259103

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