a ball is thrown straight up from the ground level, with an initial velocity of 14.7 m/s.14.7 m/s. how high is the ball thrown? assume the acceleration due to gravity is 9.8 m/s2.



Answer :

The ball's velocity decreases as it ascends, reaching a zero velocity peak at 11.025 meter's, the highest point. The speed of the ball remains constant during the toss.

The ball continues to move upward in the same direction until it reaches highest point. As the ball ascends higher, its velocity will slow down. The following is true for the ball's velocity and acceleration when it reaches its highest point. Its acceleration is not zero, despite its zero velocity. Option B is the appropriate response, thus. Any object's rate of change in velocity with respect to time is referred to as acceleration.

Maximum height reached = H = [tex]V^{2} /2g[/tex]

Maximum height reached = [tex](14.7)^{2}/(2*9.8)[/tex]

                                          = 11.025 meters

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