Answer :
The total time taken by the ball to return to the ground level is 3seconds.
given initial velocity u= 14.7 m/sec
g = 9.8 m/sec.
[tex]v^{2} = u^{2} + 2as[/tex]
The final velocity, V= O, because it reached Final point so ,
0 = [tex]14.7^{2}[/tex] + 2 ( - g ) s
0 = [tex]14.7^{2}[/tex] + 2 ( - 9 .8 ) s
S = [tex]14.7^{2}[/tex] /2x9.8 = 11. 025 mts.
1st half of travel.
Final velocity = 0.
V = u + at
V= O and u = 14. m/sec
a = -g
0 = 14.7 - 9.8 t + tdown = 14.7/9.8 = 1.5 sec
similarly tdown = 1.5 sec.
So, total time taken = 1. 5 + 1.5 = 3 sec.
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