Answered

work of 2 joules is done in stretching a spring from its natural length to 16 cm beyond its natural length. what is the force (in newtons) that holds the spring stretched at the same distance (16 cm)? don't forget to enter the correct units.



Answer :

Force (in newtons) that holds the spring stretched at the same distance is

694.44 N/m.

Work = 1/2 . k . x^2

Force = 2W/x = 62.5 N

5 = 1/2 * k *(0.12)^2

k = 694.44 N/m

The equilibrium position of a metal spring is altered when it is stretched or compressed. As a result, a restoring force is applied, which tends to cause the spring to retract back to its starting position. The term "spring force" refers to this force. In elastic materials, it manifests as a contact force.

The force constant is known as k. The force is opposite to the displacement, which means it displaces the spring from its equilibrium position, hence the force's negative sign. Both spring extension and compression are governed by this equation. Using a spring tester, the force may be determined.

Learn more about Spring here:

https://brainly.com/question/14159361

#SPJ4

 

Other Questions