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the shopper goes down the next aisle, pushing horizontally and maintaining the same speed as before. if the work done by frictional forces doesn't change, would the shopper's applied force be larger, smaller, or the same?



Answer :

a)The work done by the shopkeeper on cart move is 2655.300J.

b)kinetic energy is to be zero.

c)The work done is less than before case.

(a) Consider the formula for work done of shopper is given by

Fcos0 x1        (1)

Here, F-Force

θ -Theta makes angle between force and direction

L -Length of the cart

Substitute force for '57' and θ for '25' and / for '51.4' in equation(1)

57x cos(25)x51.4 = 2655.300J

Thus,

The work done by the shopper on the cart moves is 2655.300J

(b):Here, Consider, the net work done of cart is to be zero.

So, the change in kinetic Energy is to be zero.

C) Consider,

Force(F)= ug + uFcosθ=f

Here,

Mg-weight of the cart

θ -makes angle between the force and direction

Thus umg

Force(F)= (1-sine)

Here,

He pushes the cart is to be horizontally so theta will be zero. θ = 0

Learn more about Work done here:

https://brainly.com/question/10334435

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