you slide a slab of dielectric between the plates of a parallel-plate capacitor while keeping the charges on the plates constant. what happens to v, the potential difference between the two plates, and u, the potential energy of the capacitor?

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26-10-2022
Physics

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you slide a slab of dielectric between the plates of a parallel-plate capacitor while keeping the charges on the plates constant. what happens to v, the potential difference between the two plates, and u, the potential energy of the capacitor?

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SancharyBhattacharya SancharyBhattacharya · Answer 1 · 2022-10-29T04:30:48-04:00

Decrease in potential difference causes decrease in potential energy.

A dielectric produces an internal electric field when it is exposed to an electric field because the dielectric is polarized. The potential difference between the plates is caused by the internal electric field within the dielectric, which is in the opposite direction of the field between the plates of the capacitor. As a result, the effective electric field between the plates of the capacitor diminishes.

E = ΔV/Δr

Where, Δr = distance between plates, which is constant

Potential energy of a capacitor is;

U = (1/2)qΔV

Where, Charge is constant .

Therefore, potential energy U likewise drops as a result of the potential difference V being smaller.

Learn more about the Electric potential with the help of the given link:

https://brainly.com/question/14762028

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