a light beam strikes a peice of glass at an angle of incidence of 47. the beam contains two wavelengths 450 nm and 700 nm, for which the indices of refraction are 1.4831 and 1.4754 respectively. what is the angle between the two refracted beams



Answer :

Angle between the two refracted beams will be - 0.17

How to find the angle?

The angle of incidence of light beam, θ = 47 degree For the light of wavelength 450.0 nm, glass has index of refraction n1 = 1.4831 For the light of wavelength

first wavelength, λ1 = 450 nm

second wavelength, λ1 = 700 nm

first refractive index, μ1 = 1.4831

second refractive index, μ1 = 1.4754

Let the angle of refraction for the first wavelength is r1 and for the second wavelength is r2.

Using Snell’s law

Sin r1 = sin 47/1.4831

Sin r1 = 0.493125

r1 = 41.48 degree

Sin r2=Sin 47/1.4754

Sin r2 = 0.4956

r2 = 41.65degree

Angle between the two refracted beams = r2 – r1 = 41.65-41.48 = 0.17

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