Answer :
Angle between the two refracted beams will be - 0.17
How to find the angle?
The angle of incidence of light beam, θ = 47 degree For the light of wavelength 450.0 nm, glass has index of refraction n1 = 1.4831 For the light of wavelength
first wavelength, λ1 = 450 nm
second wavelength, λ1 = 700 nm
first refractive index, μ1 = 1.4831
second refractive index, μ1 = 1.4754
Let the angle of refraction for the first wavelength is r1 and for the second wavelength is r2.
Using Snell’s law
Sin r1 = sin 47/1.4831
Sin r1 = 0.493125
r1 = 41.48 degree
Sin r2=Sin 47/1.4754
Sin r2 = 0.4956
r2 = 41.65degree
Angle between the two refracted beams = r2 – r1 = 41.65-41.48 = 0.17
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