an economics class consists of 35 students. the mean and variance of recent test was 70% and 25(%)2, respectively. exam scores were negatively skewed. determine the number of students who scored less than 60 or more than 80.



Answer :

The number of students who scored less than 60 or more than 80 is atmost 9.

What is mean and variance?

A measurement of central dispersion is the mean and variance.

The average of a group of numbers is known as the mean.

The variance is calculated as the square root of the variance.

Chebyshev's rule is applicable for any distribution. If distribution is a normal distribution, then we can use empirical rule.

step: 2

Given mean is 70 and variance is 25.

We know standard deviation is square root of variance. So

 σ = SD =√25

    = 5

So the standard deviation is 5.

Here

60=70−2×5

80=70+2×5

So between 60 and 80 is within 2 standard deviation about mean.

So at least 75% are between 60 and 80.

Then percentage outside this is at most 25%.

Outside this means less than 60 more than 80.

So at most 25% of total data are less than 60 more than 80.

We have total 35 students.

25% of 35 students = 0.25*35

= 8.75

number of students who scored less than 60 or more than 80 is atmost 9

To know more about mean and variance please visit:

https://brainly.com/question/15811075

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