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a high energy pulsed laser emits a 2.9 ns long pulse with average power of 2.38 tw.. the beam is 0.41 cm in radius. what is the energy delivered in each pulse. what is the average value of the magnitude of the electric field



Answer :

Pulse emitted - 2.9ns= 2.9*10(-9)s

Radius - 0.41cm

Power- 2.38*10''w

what is the energy delievered?

Energy = U=P*t

           =2.9*10(-9)*2.38*10''

           =690Joule

What is the value of electric field?

Electric field will be  square root of power over absolute not times pi times are squared times the speed of light.

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