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a rugby player passes the ball 8.25 m across the field, where it is caught at the same height as it left his hand. at what angle was the ball thrown if its initial speed was 12.0 m/s, assuming that the smaller of the two possible angles was used?



Answer :

Of the two possible angles, the smaller angle is θ = 17.075°.

What is the formula for range?

The distance between a projectile's launch point and its point of impact with the ground, assuming it is fired from the ground, is referred to as the range.

R = [u²sin (2θ)]/g

Given values;

Range of pass; R = 8.25  m

Speed; u = 12 m/s

R = [u²sin (2θ)]/g

Thus;

8.25  = 12² × (sin(2θ))/9.8

(sin(2θ)) = ( 8.25 × 9.8)/12²

(sin(2θ)) = 0.5614

2θ = sin⁻¹(0.5614)

2θ = 34.15

θ =34.15/2

θ = 17.075°

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