a 15cm long solenoid with radius 2.5 cm is closely wound with 600 turns of wire. the current in the windings is 8 a. what is the magnitude of the magnetic field generated in the center of the coil? (in mt



Answer :

An electromagnet known as a solenoid creates a regulated magnetic field using a helical coil of wire whose length is significantly higher than its diameter. When an electric current is run through the coil, it can create a consistent magnetic field inside a defined region of space.

N = 600, L = 0.15 m, r = 2.5 cm.

I = 8 A

uo*N*I/L = B

40 mT is equal to B = (4*pi*10-7*600*8)/0.15 B.

15 centimeters in length, 600 round Coys, and a radius of zero point seven and fifty centimeters. It transports an eight amp current. to locate the magnetic field away from the lone in the center. The magnetic field at the solenoid's center is determined by B, I, and l, where B is equal to mu zero and I is equal to and by l. I'm going to substitute the values now. Mu 0 is 45 into 10 to the power – 7 times. Tesla will receive a 0.40 answer.

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