Answer :
Equation Q/A = E Electric Field within a parallel plate capacitor
∴ Q = E*Aε
E = 10^6 N/C
A = 4*4 = 16cm^2 = 16 * 10^-4 m^2
ε = 8.852 * 10^-12 F/m
Q = +/- 10^6 * 16 * 10^-4 * 8.852 * 10^-12
= +/- 141.6 * 10^-10 C
= +/- 14.2 nC
You can think of an electric field as a physical field that surrounds all charged particles and pulls on them all.
Before the dielectric breaks down, a parallel plate capacitor can only hold a certain amount of energy. It can be stated as follows: The parallel plate capacitor is a device that uses two parallel plates connected across a battery to create an electric field between them.
A nonmetallic component of a circuit is made in touch with using an electrode, an electrical conductor. Depending on the type of battery, electrodes are a crucial component that can be made of a range of materials.
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