you need to determine the density of a ceramic statue. if you suspended from a spring scale, the scale reads 28.4 n. if you than lower the statue into a tab of water, so that it is completely submerged, the scale reads 17.0 n. what is the statue density?



Answer :


The density of the ceramic statue is "2495.5 kg/m³".
This question involves the concepts of density, weight, volume, and buoyant force.

First, we will find out the mass of the statue:

W=mg
m=W/g
where,
W = hanging weight of statue = 28.4 N
g = acceleration due to gravity = 9.81 m/s²

Therefore,
28.4/9.81
m= 2.9kg

Now, we will find out the volume of the statue.
The difference, in weight of the statue upon submerging, must be equal to the buoyant force applied by the water. This buoyant force is equal to the weight of the volume of water displaced, which is equal to the volume of the statue.

V = 1.16 x 10⁻³ m³

Density= 2.9/1.16 x 10^-3
=2495.5kg/m^3

Therefore, the stature density is 2495.5 kg/m^3.

To learn more about buoyant force, click:
brainly.com/question/21990136?referrer=searchResults

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