Answer :
The total tangential speed = 3.56 m/s
, r =2 m ,
t =44sw
=17rpm = 17*2*3.14/60
= 1.7793 rad/swo =
01) from rotational kinematic equation
w =wo+t1.7793 =0 + *44 =0.0404 rad/s^2
(2) from rotationla kinematic equation
w^2 -wo^2 = 21.7793*1.7793
= (2*0.0404*)=39.18 rad
3) v =rw =2*1.7793
tangential speed = 3.56 m/s
What is average angular acceleration?
A spinning object's change in angular velocity per unit of time is expressed quantitatively as angular acceleration, also known as rotational acceleration. It is a vector quantity with either one of two predetermined directions or senses and a magnitude component.
The formula for average angular acceleration is: a = change in velocity divided by change in time. a=(w2−w1)/(t2−t1) a = ( w 2 − w 1 ) / ( t 2 − t 1 ) . w2 represents the final velocity measured in radians per second. w1 represents the initial velocity measured in radians per second.
Therefore, tangential speed = 3.56 m/s
To learn more about acceleration,
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