a spring is 14cm long when relaxed. its stiffness is 14n/m. you push the spring, compressing it so its length is now 8cm. what is the magnitude of the force the spring now exerts on your hand?



Answer :

1.68 Newton  is the magnitude of the the spring  force now exerts on your hand.

Stiffness of spring  Length of spring when it relaxed= 14cm

when we compressed the spring its length become =8cm

So Compressed length (x) = 0.08 m

magnitude of the force,  the spring exerts on your hand is

[tex][| vec|F|=k|x|],[ vecF=24N/m*0.08m][/tex]

F=1.92 newton

Each end of a spring is pushed apart when it is compressed by a force whose size is proportional to the length deviation from the equilibrium length.A force pushing either end toward the other when a spring is extended has a magnitude proportional to the length increase from the equilibrium length

The force a spring applies to items fastened to its ends is proportional to the distance the spring travels from its equilibrium length and is always pointed in the direction of equilibrium.

To know more about  spring  force visit : https://brainly.com/question/14655680

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