calculate the buoyant force due to the surrounding air on a man weighing 800 n . assume his average density is the same as that of water. suppose that the density of air is 1.20 kg/m3 . express your answer to two significant figures and include the appropriate units.



Answer :

0.96 Newton is the buoyant force due to the surrounding air on a man weighing 800 n .

buoyant force = weight of equal volume of air

= Volume×density of air × g = Weight of man × density of air /density of man

Density of air at 0 degrees celsius = 1.20 kg/m^3

Buoyant force = 800 ×1.20 /1000 = 0.96 N

When a body is totally or partially submerged in a fluid, there is an upward push force on the body known as buoyant force. The buoyant force always moves in a vertical direction. This force has no horizontal component, which is zero. The center of buoyancy is the location where the buoyant force acts. Large hot gas balloons may soar into the sky and ships can float on the water's surface because to this power.

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