what is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (take the static coefficient of friction of rubber on concrete to be 1.0.)

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26-10-2022
Physics

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what is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (take the static coefficient of friction of rubber on concrete to be 1.0.)

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rafikiedu08 rafikiedu08 · Answer 1 · 2022-10-29T09:48:18-04:00

The question is incomplete, however, 39.2 velocity is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding

Consider the net force acting horizontal component of friction [tex](\mu _sN \cos \theta)[/tex] and normal force Acting in horizontal component of friction [tex](N sin \theta)[/tex] , So the sum of force is

[tex]mv_max^2/r=N sin \theta+\mu _sN cos \theta[/tex]

Consider the net force acting vertical component of friction [tex](N cos \theta)[/tex] and normal force acting in Vertical component of friction [tex](\mu _sN sin \theta)[/tex] the wight of car is perpendicular to the force (-mg)

[tex]mg=N cos \theta-\mu _sN sin \theta[/tex]

[tex]v_max^2/rg=sin \theta+\mu _scos \theta/cos \theta-\mu _ssin \theta[/tex]

[tex]\nu_max=\sqrtrgsin \theta+\mu _scos \theta/cos \theta-\mu _ssin \theta[/tex]

[tex]" Substitute, "80" "m" for ' "r,,9.81" for ' "g" ', "18.0" for "\theta" and "1.0" for\mu_s[/tex]

after solving

[tex]v_max=39.2 m/s[/tex]

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