The mass of NaCl(s) (MW 58.44) would have to be added to 800 ml of water so that the resulting solution has the same freezing point as the cucl2(aq) solution assuming the ideal solution is 11.7 g
- The freezing point of a solution is lowered by the addition of solute particles. In order to have the same effect on the freezing point as the CuCl2 solution, 11.7g of NaCl must be added.
- The depression in the freezing point is a colligative property.
- It depends on the number of solute particles.
- There are many types of colligative properties namely elevation in boiling point, vant Hoff factor, etc.
To learn more about colligative properties visit:
brainly.com/question/12538175
#SPJ4