Answer :
3.5 Newton is the average force applied by the rocket engine to the rocket.
we have given data.
mass m = 0.5 kg
initial speed u = 0
final speed v = 70 m/s
time t = 10 sec
acceleration a = v-u/t
a = 70-0/10 = 7 m/s^2
from the relation
f = ma
f = 0.5×7 = 3.5 N
The direction of the applied force determines the change in a body's linear momentum, which changes at a rate that is directly proportional to the force.
The SI unit of force is the Newton. It is described as the force that propels a mass of 1 kilogram at an acceleration of 1 meter per second squared. Its sign is the capital letter N, which is represented as 1N=1 kg m s^2. 1N=1 kilogram m s^−2.
To know more about force visit : https://brainly.com/question/13191643
#SPJ4
