The cannonball has to travel 4.4 m extra due to the wind.
The cannonball is fired. So it acquired some velocity. Then there must be some resistance from the air or wind resistance. And here we ignore such resistances and assume everything to be negligible. But, in this case we need to find the extra distance that cannonball had to travel due to wind.
The cannonball is dropped in vertical from the rest.
Given,
mass of cannonball = 5 kg
velocity of cannonball = 62 m/s
Height of the cliff = 18 m high cliff
Force = 12 N
So,
t = √ (2h/g) = √(2(18)/9.8) = 1.89 s
Without the tail wind, the cannonball travels horizontally
d = vt = 62 x (1.89) = 117 m
The tailwind exerts a constant acceleration on the cannonball of
a = F/m = 12/5.0 = 2.4 m/s²
The average horizontal velocity during the flight is
v(avg) = (62 + (62 + 2.4(1.89)) / 2 = 64.25 m/s
so the distance with tailwind of cannonball is
d = v(avg)t = 64.25(1.89) = 121.432 m
The extra distance is 121.432 - 117 = 4.432 = 4.4 m
Thus, the extra distance the cannonball travels due to the wind is 4.4m.
To learn more about cannonball, refer: https://brainly.com/question/24977839
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