a 40 kg child rides on a circus ferris wheel that takes her around a vertical circular path with a radius of 40 m every 16 s. what is the magnitude of the net force on the child at the highest point on this trajectory?



Answer :

When the child uses the ferris wheel, this means the child is undergoing circular motion.

A circular motion is  type of motion when a body undergoes the rotation along a circular path. This can either be uniform or non-uniform motion.

Given:

Mass of child, m = 40 kg

Radius of the ferris wheel, r = 40 m

Time it takes to complete the circular path = 16 seconds

Here, we need to find the speed of the ferris wheel.

It is the speed in a circular motion.

So,

Speed of the ferris wheel, v = [tex]\frac{distance}{time}[/tex]= [tex]\frac{40 m}{16 s}[/tex]= 2.5 m/s

Now, that we got the speed, so the force that will be exerted in this circular motion at the HIGHEST POINT will be given by the equation:

F = F₁ - F₂  ................(1)

Here,

F₁ = gravitational force on the child

F₂ = the centripetal force.

Gravitational Force, F₁ = mg

Here g is acceleration due to Earth's gravity.

Centripetal force, F₂ = [tex]\frac{mv^{2} }{r}[/tex]

So, we get the equation (1) as:

F = mg - [tex]\frac{mv^{2} }{r}[/tex]

F = 40*9.8 - [tex]\frac{40*(2.5)^{2} }{40}[/tex]

F = 392 - 6.25

F = 385.75 N

Hence, the net force exerted on the child at the highest point is in this circular motion is 385.75 N

To know more about the circular motion, refer: https://brainly.com/question/15183370

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