Answer :
The intensity of an electromagnetic wave with a peak electric field strength of 125 v/m is 20.74 W/[tex]m^{2}[/tex]
EM waves are another name for electromagnetic waves. Electromagnetic radiations are made out of electromagnetic waves that are created when an electric field interacts with an attractive field.
The intensity of electromagnetic wave: The energy crossing per unit area held perpendicular to the direction of electromagnetic wave propagation.
the intensity is given by,
I = 0.5 × c × [tex]e_{0}[/tex] × [tex]E^{2}[/tex]
it is given that, E = 125 V/m,
and c = [tex]3810^{8}[/tex] m/sec,
[tex]e_{0}[/tex] = 8.85 × [tex]10^{-12}[/tex],
so,
I = 0.5 × 3 × [tex]10^{8}[/tex]× 8.85 × [tex]10^{-12}[/tex] × 125 × 125
Thus, I = 20.7 W/[tex]m^{2}[/tex]
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