The mass of the sample 10.0478g.
The amount of heat gained or lost by a sample (q) can be calculated using the equation q = mcΔT, where m is the mass of the sample, c is the specific heat, and ΔT is the temperature change.
[tex]$Q=m C p \Delta T$[/tex]
Where:
[tex]$\begin{aligned}&Q=\text { heat } \\&m=\text { mass } \\&C p=\text { sp. heat } \\&\Delta T=\text { temperature change }\left(T_2-T_1\right)\end{aligned}$[/tex]
Some data are provided in the problem like [tex]$Q=420$[/tex]Joules
[tex]$T_2=20^{\circ} C$[/tex]
[tex]$T_1=10^{\circ} C$[/tex]
m = Q/ (c_p* ΔT)
m= 420/(4.18 *(20-10))
m = 10.0478g
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