Emission series does this photon belongs to n=1. The H atom starts in the ground state, n = 1, which has an energy of -13.6 eV.
When a hydrogen atom returns to its ground state after being excited, it produces a photon with wavelength λ. The excited state's quantum number, n, will be: if R is the Rydberg constant
As we know, [tex]$\frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{1^2}-\frac{1}{\mathrm{n}^2}\right]$[/tex]
[tex]\frac{\left(\mathrm{n}^2-1\right)}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}}$[/tex]
[tex]$n=\sqrt{\frac{\lambda R}{\lambda R-1}}$[/tex]
[tex]n=\sqrt{\frac{95 \times(1.09 \times 10^7) }{95 \times1.09 \times 10^7-1} }[/tex]
n=1
For his theoretical investigations on spectral series, Rydberg is most known. He was able to calculate the relationships between the different lines in the spectra of chemical elements using wavenumbers rather than wavelengths.
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