while taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second on a runway that is 70. meters long. what is the magnitude of the acceleration of the jet?



Answer :

11.4m/s^2 is the magnitude of the acceleration of the jet while taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second.

[tex]v^2-u^2=2as[/tex] in this

v = final velocity

u =initial velocity

a = acceleration

s =displacement

the data, we have got

u = 0 (it starts from rest)

v = 40 m/s (final velocity)

s = 70 m ( run-way length)

now, put in the equation

[tex]a=v-u/t=(40^2-0)/2(70)=11.4m/s^2[/tex]

When a point or object accelerates or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing. All other movements accelerate as a result of these factors.

To know more about  acceleration visit : https://brainly.com/question/13975357

#SPJ4

Other Questions