Answer :
11.4m/s^2 is the magnitude of the acceleration of the jet while taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second.
[tex]v^2-u^2=2as[/tex] in this
v = final velocity
u =initial velocity
a = acceleration
s =displacement
the data, we have got
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m ( run-way length)
now, put in the equation
[tex]a=v-u/t=(40^2-0)/2(70)=11.4m/s^2[/tex]
When a point or object accelerates or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing. All other movements accelerate as a result of these factors.
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