The total reactive power absorbed by the line is: 120-J 160 VA
Given that, a load of 30 - j 40 is connected to a source of 100 v with a phase angle of 30o , through a transmission line with an inductive reactance of 80 ohms.
[tex]current, $I=I_L=\frac{100 \angle 30^{\circ}}{30-j 40+j 80}=\frac{100 \angle 30^{\circ}}{30+j 40}$[/tex]
[tex]$=2 \angle-23.13^{\circ}$[/tex]
[tex]$\begin{aligned} V_L &=\left(100\left(30^{\circ}\right)-I(j 80)\right.\\ &=\left(100 < 30^{\circ}\right)-(2 L-23.13)(j 80) \\ &=100 L-76.26 \text { volts. } \end{aligned}$[/tex]
[tex]$\begin{aligned} \text { Power delivered toads }=& V_l I_L^* \\=&(100 < -76.26)(2 L-23.13)^* . \\=&(100 < -76.26)(1.839-j 0.786)^* \\ &=(100 < -76.26)(1.839+j 0.786) \\ &=(100 < -76.26)(2 L+23.13) \\ S &=120-j 160 \mathrm{VA} \end{aligned}$[/tex]
The component of complex power known as reactive power pertains to energy storage and retrieval rather than consumption. Real power, which really does work, and reactive power, which permits transformers to change, generators to produce, and motors to rotate, are the two types of power found in an AC power system.
To learn more about reactive power visit:https://brainly.com/question/23230296
#SPJ4
