The desired amount of the anhydrous compound is 71.20 g.
Molecular mass of MnSO4 = 151 g/mol.
Molecular mass of manganese sulfate dihydrate (MnSO4.2H2O) = 187 g/mol.
The dehydration reaction occurs as following-
MnSO4.2H2O => MnSO4 + 2H2O
From 187 g of hydrate we get 151 g of anhydrous MnSO4.
So, 57.5 g of anhydrous MnSO4 will be obtained from (187 × 57.5 )/151 = 71.20 g of hydrate.
“Dehydration reactions can be defined as the chemical reactions in which a water molecule is eliminated from the reactant molecule. The process of combination of two molecules with the elimination of water molecules is called dehydration synthesis.”
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