For the given equation, we will find the value of (a) to find the equivalent equations.
First equation:
[tex]\begin{gathered} 3a+6=15 \\ 3a=15-6 \\ 3a=9 \\ a=\frac{9}{3}=3 \end{gathered}[/tex]
Second equation:
[tex]\begin{gathered} 3a=9 \\ a=\frac{9}{3}=3 \end{gathered}[/tex]
Third equation:
[tex]\begin{gathered} a+2=5 \\ a=5-2 \\ a=3 \end{gathered}[/tex]
Fourth equation:
[tex]\begin{gathered} \frac{1}{3}a=1\rightarrow(\times3) \\ 3\cdot\frac{1}{3}a=3\cdot1 \\ \\ a=3 \end{gathered}[/tex]
As shown all the equations given the same value of a = 3
So, the answer will be Y
