Answer :

Given:

The first term is, FT = z²

The middle term is, MT = -30 z

Therefore, the last term can be calculated as,

[tex]LT=\frac{MT^2}{4FT}[/tex]

Substituting, we have,

[tex]LT=\frac{(-30z)^2}{4\times z^2}=\frac{900}{4}=225[/tex]

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