Answer :
C₇H₆O₃ (aq) + CH₃COOH (aq) ------> C₉H₈O₄ (s) + H₂O (l)
We have to find the mass of aspirin (C₉H₈O₄) produced by 1.00 * 10² moles of salicylic acid (C₇H₆O₃). Before we calculate the mass we have to determine the moles of aspirin that we can get from those moles of salicylic acid.
According to the coefficients of the equation 1 mol of salicylic acid (C₇H₆O₃), when reacting with excess CH₃COOH, will produce 1 mol of aspirin (C₉H₈O₄). We can use that relationship to find the number of moles of aspirin.
moles of aspirin = 1.00 * 10² moles of salicylic acid * 1 mol of aspirin/(1 mol of salicylic acid)
moles of aspirin = 1.00 * 10² moles
Now we know that 1.00 * 10² moles of aspirin are produced. Let's find the mass using the molar mass of aspirin (C₉H₈O₄).
atomic mass of C = 12.01 amu
atomic mass of H = 1.01 amu
atomic mass of O = 16.00 amu
molar mass of C₉H₈O₄ = 9 * 12.01 + 8 * 1.01 + 4 * 16.00
molar mass of C₉H₈O₄ = 180.17 g/mol
mass of aspirin = moles of aspirin * molar mass of aspirin
mass of aspirin = 1.00 * 10² moles * 180.17 g/mol
mass of aspirin = 18017 g
mass of aspirin = 1.80 * 10⁴ g
Answer: 1.80 * 10⁴ g is possible to get from 1.00 * 10² moles of salycilic acid.
