Answered

Determine the empirical formula for each of the following compounds:1) 48% zinc and 52% chlorine2)62.6% Pb, 8.4% N, and 29% O3) 19% tin and 81% iodine4) 44.9% K, 18.4% S, and 36.7% O



Answer :

Answer:

ZnCl₂

Explanations:

In order to determine the empirical formula, we will follow the steps below:

1) Convert the percentage of each element to mass

Mass of Zinc = 48grams

Mass of Chlorine = 52 grams

2) Determine the moles of each element

Moles of Zn = mass/molar mass

Moles of Zn = 48/65.38 = 0.7342moles

Moles of Cl = 52/35.453

Moles of Cl = 1.4667 moles

3) Divide the moles by the lowest ratio

Ratio of Zn = 0.7342/0.7342 = 1

Ratio of Cl = 1.4667/0.7342 ≈ 2.0

4) Determine the empirical formula of the compound

Empirical formula = ZnCl₂

Hence the empirical formula of the compound is ZnCl₂

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