Answer :

The number of ways to arrange x successes among n trials is equal to  (  n! ) / ( x! ( n - x )! ) .

We need o find the number of  ways to arrange x successes among n trials. And to find  the number of  ways to arrange x successes among n trials we will use the formula mentioned below;

(  n! ) / ( x! ( n - x )! )

Here, to find the value of n! and x! we can use the formula mentioned below;

n! = n × ( n -1 ) ×  ( n - 2 ).............. ×1

x! = x (x - 1) ( x - 2 ).............×1

Thus, we can conclude that  (  n! ) / ( x! ( n - x )! ) represents the number of ways to arrange x successes among n trials.

To know more about Factorial refer to the link:

https://brainly.com/question/25997932

#SPJ4

Other Questions