7) 8 increased by a number is written as 8+y
three times a number is: 3x
4 more than the number is: 4+x
Thus, the expression is
[tex]8+3x\ge4+x[/tex]Solving for x,
[tex]\begin{gathered} \Rightarrow8+3x-x\ge4+x-x \\ \Rightarrow8+2x\ge4 \\ \Rightarrow-8+8+2x\ge-8+4 \\ \Rightarrow2x\ge-4 \\ \Rightarrow x\ge-\frac{4}{2}=-2 \\ \Rightarrow x\ge-2 \end{gathered}[/tex]The answer is x>=-2