Answer :

[tex]\begin{gathered} \frac{2x^3-13x^2+9x-16}{x-6} \\ \end{gathered}[/tex]

From the division result above,

The quotient is

[tex]2x^2-x+3[/tex]

While the remainder is 2

The result of the division can be written in the form

[tex](2x^2-x+3)\text{ +}\frac{2}{x-6}[/tex]

The answer is

[tex]\frac{2x^3-13x^2+9x-16}{x-6}=\text{ }(2x^2-x+3)\text{ +}\frac{2}{x-6}[/tex]

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