Solution:
Given that a = 3, b = 4
To solve:
[tex]\begin{gathered} A)\text{ 3b-a}^2 \\ B)\text{ 2b}^2-7a \end{gathered}[/tex]
To solve, we substitute the values of a and b into the given expressions.
Thus,
A)
[tex]\begin{gathered} 3b-a^2=3(4)-(3)^2 \\ =12-9 \\ =3 \end{gathered}[/tex]
B)
[tex]\begin{gathered} 2b^2-7a=2(4)^2-7(3) \\ =32-21 \\ =11 \end{gathered}[/tex]
