Given:
Here given is 7P4 and 12C5
Required:
Evaluate both
Explanation:
here is the formula for P
[tex]nPr=\frac{n!}{(n-r)!}[/tex]so now for 7P4
[tex]7P4=\frac{7!}{(7-4)!}=\frac{7*6*5*4*3!}{3!}=7*6*5*4=840[/tex]now for 12C5
here is the formula for C
[tex]nCr=\frac{n!}{r!(n-r)!}[/tex][tex]12C5=\frac{12!}{5!(12-5)!}=\frac{12*11*10*9*8*7!}{5!7!}=792[/tex]is for 12C5
Final Answer:
7P4=840 and 12C5=792