10r^2 + 13r - 3 = 0
[tex]\begin{gathered} \frac{-b\text{ }\pm\sqrt[]{b^2\text{ - 4ac}}}{2a} \\ \frac{-13\text{ }\pm\sqrt[]{13^2\text{ - 4(10)(-3)}}}{2(10)} \\ \frac{-13\text{ }\pm\sqrt[]{169\text{ +120}}}{20} \\ \frac{-13\text{ }\pm\sqrt[]{289}}{20} \\ \end{gathered}[/tex]a = 10
b= 13
c = -3
a) From the result, we conclude that
N = -13 D = 289 M = 20
b)
[tex]\begin{gathered} \frac{-13\text{ }\pm17}{20} \\ r1\text{ = }\frac{-13\text{ + 17}}{20}\text{ r2 = }\frac{-13\text{ - 17}}{20} \\ r1\text{ = }\frac{4}{20}\text{ r2 = }\frac{-30}{20} \\ r1\text{ = }\frac{1}{5}\text{ r2 =-}\frac{15}{10\text{ }}=-\frac{3}{2} \\ \end{gathered}[/tex]
r1 = 1/5 r2 = -3/2