Let us write out the formula for discriminant,
[tex]D=b^2-4ac[/tex]
Let us write out the general quadratic equation,
[tex]ax^2+bx+c=0[/tex]
Let us write out the given equation,
[tex]x^2+11x-10=0[/tex]
Comparing the two equations, and getting the values for a, b and c.
[tex]\begin{gathered} a=1 \\ b=11 \\ c=-10 \end{gathered}[/tex]
Let us now solve for the discriminant,
[tex]\begin{gathered} D=11^2-4(1)(-10) \\ D=121+40 \\ D=161 \end{gathered}[/tex]
Since the discriminant is positive, the quadratic has two real solutions.
