Explanation
the slope-intercept form of a line is given by
[tex]\begin{gathered} y=mx+b \\ where\text{ m is the slope } \\ b\text{ is the y -intercept} \end{gathered}[/tex]
so
Step 1
given
[tex]y=6x+3[/tex]
a)let
[tex]y=mx+b\rightarrow y=6x+3[/tex]
hence
slope=m=6
y-intercept =3
b)graph the y-intercept
the y intercept has the coordinate ( 0,b)
(0,3) in our case, so we have a point from the line
b) now, slope is thhe ratio of the vertical to the horizontal distance between
so,
[tex]slope=\text{ }\frac{rise}{run}=6[/tex]
so, for 1 unit in the x axis , it moves 6 units in the y-axis
so the second point is (1,9), the graph would be
finally, draw the line
I hope this helps you
